# the f(n) of MCS

## the f(n) of MCS

Let f(n) = 1/(2^n)

where n >= 1.

as n approaches infinity f(1) + f(2) + ... + f(n) approaches 1.

f(n) is the percentage number of students in n year level in the department of MCS.

Can you prove that a certain student in a year level will have a 50% chance to proceed to the next year level?

Isn't math fun?

someone prove this... saun ra kaau... math15 + math16 + math35...

edit: f(n) was wrong lol... fixed it... but its so easy now... x.x it looked harder when it was wrong lol u dont need induction anymore... *sadface*

where n >= 1.

as n approaches infinity f(1) + f(2) + ... + f(n) approaches 1.

f(n) is the percentage number of students in n year level in the department of MCS.

Can you prove that a certain student in a year level will have a 50% chance to proceed to the next year level?

Isn't math fun?

someone prove this... saun ra kaau... math15 + math16 + math35...

edit: f(n) was wrong lol... fixed it... but its so easy now... x.x it looked harder when it was wrong lol u dont need induction anymore... *sadface*

Last edited by i am furfur on August 2nd 2009, 8:07 pm; edited 3 times in total

_________________

Never be afraid to share your dreams with the world, because there's nothing the world loves more than the taste of really sweet dreams...

**FTS of PSHAW...**

I'm not IMBA

I'm not IMBA

*not unless I have you...***i am furfur**- Oh My Furfur Gosh
- Number of posts : 319

Location : Beyond borders, Within worlds

Registration date : 2008-11-12

## Re: the f(n) of MCS

I don't get the f(n). If n = 2, what is f(n) or f(2)?

**Chujutsu**- Programmer
- Number of posts : 325

Location : In front of a computer

Registration date : 2009-07-08

## Re: the f(n) of MCS

Chujutsu wrote:I don't get the f(n). If n = 2, what is f(n) or f(2)?

ooops my bad.

f(n) = 1 - 1/2 - 1/3 - 1/n - ...

f(2) = 1 - 1/2

saup akong gi originally post

_________________

Never be afraid to share your dreams with the world, because there's nothing the world loves more than the taste of really sweet dreams...

**FTS of PSHAW...**

I'm not IMBA

I'm not IMBA

*not unless I have you...***i am furfur**- Oh My Furfur Gosh
- Number of posts : 319

Location : Beyond borders, Within worlds

Registration date : 2008-11-12

## Re: the f(n) of MCS

Uhh... f(3) gives 1 - 1/2 - 1/3 which is 1/6. I don't think that's at least 50% chance.

**Chujutsu**- Programmer
- Number of posts : 325

Location : In front of a computer

Registration date : 2009-07-08

## Re: the f(n) of MCS

Chujutsu wrote:Uhh... f(3) gives 1 - 1/2 - 1/3 which is 1/6. I don't think that's at least 50% chance.

f(n) is the percentage number of students in n year level

get the percentage chance of a student in a n year level going to the n+1 year level.

hmm... you have a point... i was thinking (1/2)/2=1/8 x.x

anyway there's something wrong with the function coz f(4) is already negative lol

i'll fix it after i play dota

_________________

Never be afraid to share your dreams with the world, because there's nothing the world loves more than the taste of really sweet dreams...

**FTS of PSHAW...**

I'm not IMBA

I'm not IMBA

*not unless I have you...***i am furfur**- Oh My Furfur Gosh
- Number of posts : 319

Location : Beyond borders, Within worlds

Registration date : 2008-11-12

## Re: the f(n) of MCS

(1/2)/2 in math is 1/4

**Chujutsu**- Programmer
- Number of posts : 325

Location : In front of a computer

Registration date : 2009-07-08

## Re: the f(n) of MCS

Chujutsu wrote:(1/2)/2 in math is 1/4

i know that LOL... changed the f(n) anyway

_________________

Never be afraid to share your dreams with the world, because there's nothing the world loves more than the taste of really sweet dreams...

**FTS of PSHAW...**

I'm not IMBA

I'm not IMBA

*not unless I have you...***i am furfur**- Oh My Furfur Gosh
- Number of posts : 319

Location : Beyond borders, Within worlds

Registration date : 2008-11-12

## Re: the f(n) of MCS

1/(2^n) = (1/2)^n

Since 1/2 is between zero and one, the more it is multiplied with itself, the smaller its value becomes, so...? Less chance?

Anyway, (1/2)^1 is equal to 1/2, or 50%.

Assuming it's sum of f(1), f(2),... all the way up to f(n) instead. If that was true, then simply adding f(n+1) should increase that. After all, it is impossible for (1/2)^n to become negative. Since the sum of f(1), f(2),... all the way up to f(n) is at least 50%, then that would mean the sum of f(1), f(2),... all the way up to f(n+1) is also at least 50%.

Since 1/2 is between zero and one, the more it is multiplied with itself, the smaller its value becomes, so...? Less chance?

Anyway, (1/2)^1 is equal to 1/2, or 50%.

Assuming it's sum of f(1), f(2),... all the way up to f(n) instead. If that was true, then simply adding f(n+1) should increase that. After all, it is impossible for (1/2)^n to become negative. Since the sum of f(1), f(2),... all the way up to f(n) is at least 50%, then that would mean the sum of f(1), f(2),... all the way up to f(n+1) is also at least 50%.

**Chujutsu**- Programmer
- Number of posts : 325

Location : In front of a computer

Registration date : 2009-07-08

## Re: the f(n) of MCS

Chujutsu wrote:1/(2^n) = (1/2)^n

Since 1/2 is between zero and one, the more it is multiplied with itself, the smaller its value becomes, so...? Less chance?

nope.

f(n) is decreasing but you're not looking for the population percentages per year

but the rate of passing a year level into the next.

Chujutsu wrote:

Assuming it's sum of f(1), f(2),... all the way up to f(n) instead. If that was true, then simply adding f(n+1) should increase that. After all, it is impossible for (1/2)^n to become negative. Since the sum of f(1), f(2),... all the way up to f(n) is at least 50%, then that would mean the sum of f(1), f(2),... all the way up to f(n+1) is also at least 50%.

if it's the sum then f(1) = 1/2 and f(2) = 3/4

the percentages per year level would be wrong.

f(1) + f(2) = 5/4 which is greater than 100%

is that what you mean?

whereas the original.

f(1) = 1/2, f(2) = 1/4 so on...

then f(1) + f(2) + ... f(infinity) would approximate to 1 or 100%.

anyway of course f(1) + .. + f(n) would be greater than 50% since f(1) is already 50%

_________________

Never be afraid to share your dreams with the world, because there's nothing the world loves more than the taste of really sweet dreams...

**FTS of PSHAW...**

I'm not IMBA

I'm not IMBA

*not unless I have you...***i am furfur**- Oh My Furfur Gosh
- Number of posts : 319

Location : Beyond borders, Within worlds

Registration date : 2008-11-12

## Re: the f(n) of MCS

Let's just stop. This f(n) is still broken.

**Chujutsu**- Programmer
- Number of posts : 325

Location : In front of a computer

Registration date : 2009-07-08

## Re: the f(n) of MCS

Chujutsu wrote:Let's just stop. This f(n) is still broken.

haha... the exponential function works...

anyway... you just need to prove that the ratio of f(n+1)/f(n) = 50%

_________________

Never be afraid to share your dreams with the world, because there's nothing the world loves more than the taste of really sweet dreams...

**FTS of PSHAW...**

I'm not IMBA

I'm not IMBA

*not unless I have you...***i am furfur**- Oh My Furfur Gosh
- Number of posts : 319

Location : Beyond borders, Within worlds

Registration date : 2008-11-12

## Re: the f(n) of MCS

f(1+1)/f(1) = f(2)/f(1) = (1/2)^2 / (1/2)^1 = (1/4)/(1/2) = (1/4) * 2 = 1/2

f(n+1)/f(n) = (1/2)^(n+1) / (1/2)^n = (1/2)^(n+1 - n) = 1/2

f(n+1)/f(n) = (1/2)^(n+1) / (1/2)^n = (1/2)^(n+1 - n) = 1/2

**Chujutsu**- Programmer
- Number of posts : 325

Location : In front of a computer

Registration date : 2009-07-08

## Re: the f(n) of MCS

Chujutsu wrote:f(1+1)/f(1) = f(2)/f(1) = (1/2)^2 / (1/2)^1 = (1/4)/(1/2) = (1/4) * 2 = 1/2

f(n+1)/f(n) = (1/2)^(n+1) / (1/2)^n = (1/2)^(n+1 - n) = 1/2

the end XD lol...

anyway forget the first f(n) that was broken.

_________________

Never be afraid to share your dreams with the world, because there's nothing the world loves more than the taste of really sweet dreams...

**FTS of PSHAW...**

I'm not IMBA

I'm not IMBA

*not unless I have you...***i am furfur**- Oh My Furfur Gosh
- Number of posts : 319

Location : Beyond borders, Within worlds

Registration date : 2008-11-12

## Re: the f(n) of MCS

Yeah sure

**Chujutsu**- Programmer
- Number of posts : 325

Location : In front of a computer

Registration date : 2009-07-08

## Re: the f(n) of MCS

I gotta post something here,..

....

oh,.!

Let me just say it:

"Q.E.D.

With this,

the proof is complete."

....

oh,.!

Let me just say it:

"Q.E.D.

With this,

the proof is complete."

_________________

If I had left earlier,

I would have been in time for my

*FURUGAHITO*,.?

**pbwuzherr**- Debugger
- Number of posts : 139

Registration date : 2008-11-13

## Re: the f(n) of MCS

Q.E.D.?

What is that?

What is that?

**Chujutsu**- Programmer
- Number of posts : 325

Location : In front of a computer

Registration date : 2009-07-08

## Re: the f(n) of MCS

Just breathe in slowly, and breathe out... Make sure that you won't bleed!!!

Anyway, just take it piece by piece. That's how I'd look at math at times. You don't have to take everything in all at once.

Anyway, just take it piece by piece. That's how I'd look at math at times. You don't have to take everything in all at once.

**Chujutsu**- Programmer
- Number of posts : 325

Location : In front of a computer

Registration date : 2009-07-08

## Re: the f(n) of MCS

Chujutsu wrote:Just breathe in slowly, and breathe out... Make sure that you won't bleed!!!

Anyway, just take it piece by piece. That's how I'd look at math at times. You don't have to take everything in all at once.

HUHU. salig bryt ai .

## Re: the f(n) of MCS

Hmm... Maybe I should give some tips with Math? Maybe not in here though...

Would you want some?

Would you want some?

**Chujutsu**- Programmer
- Number of posts : 325

Location : In front of a computer

Registration date : 2009-07-08

Page

**1**of**1****Permissions in this forum:**

**cannot**reply to topics in this forum